class 9 derivation of equation of motion |class 9 ch motion ncert acience | motion physics | |
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✅ In this video,
✔️ Class: 9 ✔️ Subject: Physics ✔️ Chapter: Motion ✔️ Topic Name: Equation of Motion by Graphical Method =============================================== 📢 🔥 Available (Kindergarten to 12th) all Video Subject wise Playlist https://www.pabbly.com/out/all-videos-playlist Why study from Magnet Brains? Magnet Brains is an online education platform that helps give You NCERT/CBSE curriculum based free full courses from Kindergarten to Class 12th so that you can perform well in any and all exams you give in your academic care Points covered in this video:- Equation of Motion by Graphical Method - Equation for v - t relation - These equations give relationship between u, v, t, a and distance travelled by the bodies. - Applicable on the motion of bodies with uniform acceleration. Equation for v - t relation Area under v -t graph gives displacemnet By defination of acceleration In v - t graph, S = area of trapezium ABCO S = ½ (BD + AO) X OD S = ½ (v + u) x t Putting the value of t , we get S = ½ (v + u) x (v - u)/a S = ½ v2 - vu + uv - u2 a S = ½ [v2 - u2]/ a 2aS = v2 - u2 S = A [area of trapezium ABDO] S = A [ABC + ACOD] S = ½ [AC X BC] + [AO X OD] S= ½ [t x (v - u)] + ut S = ut + ½ t [v - u] S = ut + ½ t [at] S = ut + ½ at2 |